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2x^2+27x-624=0
a = 2; b = 27; c = -624;
Δ = b2-4ac
Δ = 272-4·2·(-624)
Δ = 5721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{5721}}{2*2}=\frac{-27-\sqrt{5721}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{5721}}{2*2}=\frac{-27+\sqrt{5721}}{4} $
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